blob: 593959684c8e1e201780960bc14f91f55142f1bc [file] [log] [blame]
#!/usr/bin/env python
# Copyright 2019 Google LLC.
# Use of this source code is governed by a BSD-style license that can be
# found in the LICENSE file.
Generate a source file containing the given binary data.
Output type is C++.
from __future__ import print_function
import os
import struct
import sys
import mmap
def iterate_as_uint32(path):
with open(path, 'rb') as f:
s = struct.Struct('@I')
assert s.size == 4
mm = mmap.mmap(f.fileno(), 0, access=mmap.ACCESS_READ)
assert (len(mm) % s.size) == 0
for offset in range(0, len(mm), s.size):
yield s.unpack_from(mm, offset)[0]
def convert(fmt, name, src_path, dst_path):
header, line_begin, line_end, footer = fmt
assert os.path.exists(src_path)
src = iterate_as_uint32(src_path)
with open(dst_path, 'w') as o:
while True:
line = ','.join('%d' % v for _, v in zip(range(8), src))
if not line:
o.write('%s%s%s\n' % (line_begin, line, line_end))
cpp = ('#include <cstdint>\nextern "C" uint32_t {0}[] __attribute__((aligned(16))) = {{\n',
'', ',', '}};\n')
if __name__ == '__main__':
print('\n'.join('>>> %r' % x for x in sys.argv))
convert(cpp, sys.argv[1], sys.argv[2], sys.argv[3])