skia / skia / 8e712021de51eadb887c4aa6b18ceb4bf3f78f07 / . / experimental / Intersection / IntersectionUtilities.cpp

/* | |

* Copyright 2012 Google Inc. | |

* | |

* Use of this source code is governed by a BSD-style license that can be | |

* found in the LICENSE file. | |

*/ | |

#if 0 | |

// snippets that one day may be useful, unused for now... | |

// get sign, exponent, mantissa from double | |

// Translate the double into sign, exponent and mantissa. | |

long bits = BitConverter.DoubleToInt64Bits(d); | |

// Note that the shift is sign-extended, hence the test against -1 not 1 | |

bool negative = (bits < 0); | |

int exponent = (int) ((bits >> 52) & 0x7ffL); | |

long mantissa = bits & 0xfffffffffffffL; | |

// Subnormal numbers; exponent is effectively one higher, | |

// but there's no extra normalisation bit in the mantissa | |

if (exponent==0) | |

{ | |

exponent++; | |

} | |

// Normal numbers; leave exponent as it is but add extra | |

// bit to the front of the mantissa | |

else | |

{ | |

mantissa = mantissa | (1L<<52); | |

} | |

// Bias the exponent. It's actually biased by 1023, but we're | |

// treating the mantissa as m.0 rather than 0.m, so we need | |

// to subtract another 52 from it. | |

exponent -= 1075; | |

if (mantissa == 0) | |

{ | |

return "0"; | |

} | |

/* Normalize */ | |

while((mantissa & 1) == 0) | |

{ /* i.e., Mantissa is even */ | |

mantissa >>= 1; | |

exponent++; | |

} | |

#endif |