blob: 9b8a1117b1284006bf9e5051edd1c27e6ecaab89 [file] [log] [blame]
* Copyright (c) 1999-2002, International Business Machines Corporation and
* others. All Rights Reserved.
#include "unicode/unum.h"
#include "unicode/ustring.h"
#include <stdio.h>
#include <stdlib.h>
static void uprintf(const UChar* str) {
char buf[256];
u_austrcpy(buf, str);
printf("%s", buf);
void capi() {
UNumberFormat *fmt;
UErrorCode status = U_ZERO_ERROR;
/* The string "987654321.123" as UChars */
UChar str[] = { 0x39, 0x38, 0x37, 0x36, 0x35, 0x34, 0x33,
0x32, 0x31, 0x30, 0x2E, 0x31, 0x32, 0x33, 0 };
UChar buf[256];
int32_t needed;
double a;
/* Create a formatter for the US locale */
fmt = unum_open(
UNUM_DECIMAL, /* style */
0, /* pattern */
0, /* patternLength */
"en_US", /* locale */
0, /* parseErr */
if (U_FAILURE(status)) {
printf("FAIL: unum_open\n");
/* Use the formatter to parse a number. When using the C API,
we have to specify whether we want a double or a long in advance.
We pass in NULL for the position pointer in order to get the
default behavior which is to parse from the start. */
a = unum_parseDouble(fmt, str, u_strlen(str), NULL, &status);
if (U_FAILURE(status)) {
printf("FAIL: unum_parseDouble\n");
/* Show the result */
printf("\") => %g\n", a);
/* Use the formatter to format the same number back into a string
in the US locale. The return value is the buffer size needed.
We're pretty sure we have enough space, but in a production
application one would check this value.
We pass in NULL for the UFieldPosition pointer because we don't
care to receive that data. */
needed = unum_formatDouble(fmt, a, buf, 256, NULL, &status);
if (U_FAILURE(status)) {
printf("FAIL: format_parseDouble\n");
/* Show the result */
printf("unum_formatDouble(%g) => \"", a);
/* Release the storage used by the formatter */