| // Copyright 2017 The Wuffs Authors. |
| // |
| // Licensed under the Apache License, Version 2.0 <LICENSE-APACHE or |
| // https://www.apache.org/licenses/LICENSE-2.0> or the MIT license |
| // <LICENSE-MIT or https://opensource.org/licenses/MIT>, at your |
| // option. This file may not be copied, modified, or distributed |
| // except according to those terms. |
| // |
| // SPDX-License-Identifier: Apache-2.0 OR MIT |
| |
| package ast |
| |
| import ( |
| t "github.com/google/wuffs/lang/token" |
| ) |
| |
| // Eq returns whether n and o are equal. |
| // |
| // It may return false negatives. In general, it will not report that "x + y" |
| // equals "y + x". However, if both are constant expressions (i.e. each Expr |
| // node, including the sum nodes, has a ConstValue), both sums will have the |
| // same value and will compare equal. |
| func (n *Expr) Eq(o *Expr) bool { |
| if n == o { |
| return true |
| } |
| if n == nil || o == nil { |
| return false |
| } |
| if n.constValue != nil && o.constValue != nil { |
| return n.constValue.Cmp(o.constValue) == 0 |
| } |
| |
| if n.flags != o.flags || n.id0 != o.id0 || n.id1 != o.id1 || n.id2 != o.id2 { |
| return false |
| } |
| if !n.lhs.AsExpr().Eq(o.lhs.AsExpr()) { |
| return false |
| } |
| if !n.mhs.AsExpr().Eq(o.mhs.AsExpr()) { |
| return false |
| } |
| |
| if n.id0 == t.IDXBinaryAs { |
| if !n.rhs.AsTypeExpr().Eq(o.rhs.AsTypeExpr()) { |
| return false |
| } |
| } else if !n.rhs.AsExpr().Eq(o.rhs.AsExpr()) { |
| return false |
| } |
| |
| if len(n.list0) != len(o.list0) { |
| return false |
| } |
| for i, x := range n.list0 { |
| if !x.AsExpr().Eq(o.list0[i].AsExpr()) { |
| return false |
| } |
| } |
| return true |
| } |
| |
| func (n *Expr) Mentions(o *Expr) bool { |
| if n == nil { |
| return false |
| } |
| if n.Eq(o) || |
| n.lhs.AsExpr().Mentions(o) || |
| n.mhs.AsExpr().Mentions(o) || |
| (n.id0 != t.IDXBinaryAs && n.rhs.AsExpr().Mentions(o)) { |
| return true |
| } |
| for _, x := range n.list0 { |
| if x.AsExpr().Mentions(o) { |
| return true |
| } |
| } |
| return false |
| } |
| |
| // Eq returns whether n and o are equal. |
| func (n *TypeExpr) Eq(o *TypeExpr) bool { |
| return n.eq(o, false, false) |
| } |
| |
| // EqIgnoringRefinements returns whether n and o are equal, ignoring the |
| // "[i:j]" in "base.u32[i:j]". |
| func (n *TypeExpr) EqIgnoringRefinements(o *TypeExpr) bool { |
| return n.eq(o, true, false) |
| } |
| |
| // EqIgnoringRefinementsLHSReadOnly returns whether n and o are equal, ignoring |
| // the "[i:j]" in "base.u32[i:j]" and allowing n (the Left Hand Side of an |
| // assignment) to be read-only when o (the Right Hand Side) is read-write, or n |
| // to be "nptr T" when o is "ptr T". |
| func (n *TypeExpr) EqIgnoringRefinementsLHSReadOnly(o *TypeExpr) bool { |
| return n.eq(o, true, true) |
| } |
| |
| func (n *TypeExpr) eq(o *TypeExpr, ignoreRefinements bool, lhsReadOnly bool) bool { |
| for { |
| if n == o { |
| return true |
| } |
| if n == nil || o == nil { |
| return false |
| } |
| if n.id0 != o.id0 { |
| if !lhsReadOnly { |
| return false |
| } |
| switch { |
| default: |
| return false |
| case (n.id0 == t.IDRoarray) && (o.id0 == t.IDArray): |
| case (n.id0 == t.IDRoslice) && (o.id0 == t.IDSlice): |
| case (n.id0 == t.IDRotable) && (o.id0 == t.IDTable): |
| case (n.id0 == t.IDNptr) && (o.id0 == t.IDPtr): |
| } |
| } |
| if n.id1 != o.id1 || n.id2 != o.id2 { |
| return false |
| } |
| if !ignoreRefinements || !n.IsNumType() { |
| if !n.lhs.AsExpr().Eq(o.lhs.AsExpr()) || !n.mhs.AsExpr().Eq(o.mhs.AsExpr()) { |
| return false |
| } |
| } |
| if n.rhs == nil && o.rhs == nil { |
| return true |
| } |
| n = n.rhs.AsTypeExpr() |
| o = o.rhs.AsTypeExpr() |
| } |
| } |